How many gametes can be formed from AABbCc?
In this case of genotype AABbCc, A gene will give only one type of gamete, B can give two types of gametes and c can give two types of gametes. Thus, totally four types of gametes will be produced.
Complete answer
So, it results in the production of 22= 4 types of gametes. These types of genotypes that are ABC, ABc, AbC, and Abc will be found in the gametes. Thus the number of gametes produced by the plant having the genotype AABbCc is four.
The given genotype AaBbCcDd is heterozygous for 4 genes and can make 24= 16 types of gametes.
To calculate the total number of gametes that are produced by a particular genotype, a specific formula 2n is used, where n= number of heterogeneous alleles that are found in the genotype. Here, the given genotype consists of two heterogeneous alleles Bb, and Cc while one homozygous allele is AA.
The given genotype is heterozygous for two genes, this total possible gametes by it; 22 = 4. Thus, option B is correct. The gametes produced by AaBBCc are ABC, ABc, aBC and aBc.
So, the correct option is '8'.
Gametes are formed through meiosis (reduction division), in which a germ cell undergoes two fissions, resulting in the production of four gametes.
So, if there are a total of 78 chromosomes then half of its number (half of 78) is 39 chromosomes are present in the female gamete or egg cell. So, the egg cell will have 39 numbers of chromosomes. Therefore, the answer is 39 chromosomes would be present in its egg cell.
Meiosis is a type of cell division that reduces the number of chromosomes in the parent cell by half and produces four gamete cells. This process is required to produce egg and sperm cells for sexual reproduction.
In the above cross$AaBbCc \times AaBbCc$, there are three pairs of characters which are Aa, Bb, Cc. Therefore, the number of possible phenotypes are ${2^3} = 8$. Hence, the correct option is C. 8.
Is AaBbCc a genotype or phenotype?
The genotype of human skin colour is AAbbcc and AaBbcc respectively.